Tuesday, March 20, 2012
cant enter data in field
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[Quotes]') and OBJECTPROPERTY(id, N'IsUserTable') = 1)
drop table [dbo].[Quotes]
GO
CREATE TABLE [dbo].[Quotes] (
[QuoteID] [int] IDENTITY (1, 1) NOT NULL ,
[DateAdded] [datetime] NULL ,
[CustomerID] [int] NOT NULL ,
[ProductName] [varchar] (100) NULL ,
[RepID] [int] NULL ,
[QuoteNumber] [varchar] (30) NULL ,
[QuoteDate] [datetime] NULL ,
[QuoteTerm] [varchar] (10) NULL ,
[QuoteFOB] [varchar] (15) NULL ,
[QuoteNAIRep] [varchar] (30) NULL ,
[QuoteExpiration] [datetime] NULL ,
[Note] [varchar] (700) NULL ,
[Comment] [varchar] (1500) NULL ,
[OrderRequirement] [varchar] (1000) NULL ,
[Status] [varchar] (1) NULL ,
[DateClosed] [datetime] NULL ,
[ProductType] [varchar] (30) NULL ,
[ImageID] [int] NULL ,
[CloseMonth] [int] NULL ,
[CloseYear] [int] NULL ,
[ClosePercent] [int] NULL ,
[Segment] [varchar] (50) NULL ,
[AccountID] [uniqueidentifier] NULL ,
[ReplacedQuoteID] [int] NULL ,
[Lead] [varchar] (80) NULL
) ON [PRIMARY]
GO
ALTER TABLE [dbo].[Quotes] ADD
CONSTRAINT [DF_Quotes_Closed] DEFAULT ('N') FOR [Status]
GO
CREATE INDEX [idx_RepID] ON [dbo].[Quotes]([RepID]) ON [PRIMARY]
GO
CREATE INDEX [indx_CustomerID] ON [dbo].[Quotes]([CustomerID]) ON [PRIMARY]
GO
CREATE INDEX [indx_QuoteID] ON [dbo].[Quotes]([QuoteID]) ON [PRIMARY]
GO
CREATE INDEX [indx_Status] ON [dbo].[Quotes]([Status]) ON [PRIMARY]
GO
[Comment] [varchar] (1500) NULL , is where I can't enter more than 994 characters.
note - I know very little about SQL, I just had the responsibility placed on me at my job. If this is not enough information to go on to throw an idea at me please let me know what else you need.
Thanks in advanceNo such issue i just ran your script and inserted 1500 characters into the comments column....also when you define 1500 it will give you a capacity of 1500
are you using the insert statement or just entering data through enterprise manager?? cuz insert statement worked fine for me...
insert into quotes (Customerid, comment)
values (3,'Your comment goes here')
Also try to find the length of your largest column by using the following script
select len(comment)
from quotes|||i am entering the text manually. Don't know how to run an insert script.
I ran the sel script and the longest entry is 1000 chars.
would you mind telling me how to run the insert script to apply the comment to quote number 070530JB185438?|||I was able to insert the text I need using the insert script you gave, I just had to add more fields to make it apply to the correct quote...
INSERT INTO Quotes
(QuoteID, CustomerID, QuoteNumber, Comment)
VALUES ('35845', '5695', '070530jb185438', 'comment')
Thanks for the help, it is greatly appreciated.:beer:|||since quoteid is generated automatically you dont need to insert a value there...... according to your table design then customerid is the only non nullable field which needs to be present...
hence for testing purpose if you provide a query as
INSERT INTO Quotes
(CustomerID, Comment)
VALUES ('5695', 'comment')
it would still work...since all other columns are nullable......
Also to test your case you can insert a very long string in place of 'comment'... and inside single quotes of course...
other thing what you can do to test the case is use the update statement
update quotes
set comment = 'You comment goes here'
where customerid = '5695'
this will update the record which has customerid = '5695'
i.e. the record which you have just inserted in the previous post|||Here's a function to insert a 1500 character string of x's into your comment field.
INSERT INTO Quotes
(customerid, comment) VALUES ('1234', REPLACE(SPACE(1500), ' ', 'x'))
then check the length with the Len function
Sunday, March 11, 2012
Can't delete subscription
Hello,
I delete the publication, but the subscription still exists.
If I will delete the abonement I get following error 21776(Can't find Name xxx in the list of the TransPublications).
I tryed to craete the publication for the failed subscription again, but then I get the error, that a subscription for this publication still exists.
What can I do? How can I delete the subscription ?
Many thx for help!
Which SQL version are you using? Do you use scripts or UI to drop publication and subscription? Is subscription pull and located on the remote server? Could you please provide detailed repro step by step?
Thanks
Yunjing
|||hello,
we use sql server 2000 and droped the replication via tsql
subscription is push and located on the remote server. I think I must delete all informations manuell in the server protocols, but how?
thx